Math, asked by prashant355, 10 months ago

the sum of digit of a two digit number is 9 if the new number formed by reversing the digits is greater than the original number by 45 find the original number

Answers

Answered by student5649

4

Step-by-step explanation:

Lex 1st (unit) digit = x

let tens no be =9-x

original no.

= 10 (9 - x) + x + 45 = 10x 9 - x

90 - 10x + x + 45 = 9x +9

135-9x=9X+9

126=18x

X=7

Original number=10(9-7)+7

=20+7

=27

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Hope it helps you

Answered by supreetkaur35

3

hope this will help you..

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