Math, asked by sanjayyadav2370, 9 months ago

The sum of digit of a two digit number is 9.
The digit are reversed when 9 is added to the number. Find the number.

Answers

Answered by BrainlyRaaz
25

Given :

  • The sum of digit of a two digit number is 9.

  • The digit are reversed when 9 is added to the number.

To find :

  • The number =?

Step-by-step explanation :

Let, the ones digit of two digits number be, x.

Then, the tens digit of two digits number be, 9 - x.

So, the number will be, 10(9 - x) + x = 90 + 9x

After reversing the digits the number will be,

= 10x + (9 - x)

= 9x + 9.

According to the question :

➮ 90 - 9x = 9x + 9 - 9

➮ 18x = 90 - 9 + 9

➮ 18x = 90

➮ x = 90/18

➮ x = 5.

Hence,

Ones digit, x = 5

Ten's digit, 9 - x = 9 - 5 = 4

Therefore, the new number = 10 × 4 + 5 = 45

Answered by Anonymous
16

\blue{\bold{\underline{\underline{Answer:}}}}

 \:\:

 \green{\underline \bold{Given :}}

 \:\:

  • Sum of digit of a two digit number is 9

 \:\:

  • Digit gets reversed when 9 is added to the number.

 \:\:

 \red{\underline \bold{To \: Find:}}

  • The original number

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

Let the tens digit be 'x'

Let the ones digit be 'y'

 \:\:

 \underline{\bold{\texttt{Original number :}}}

 \:\:

\purple\longrightarrow  \sf 10x + y

 \:\:

 \underline{\bold{\texttt{Reversed number :}}}

 \:\:

\purple\longrightarrow  \sf 10y + x

 \:\:

 \purple{\underline \bold{According \: to \: the \ question :}}

 \:\:

 \bf \dashrightarrow x + y = 9 -------(1)

 \:\:

Also,

 \:\:

 \sf \longmapsto 10x + y + 9 = 10y + x

 \:\:

 \sf \longmapsto 10x - x + y - 10y = -9

 \:\:

 \sf \longmapsto 9x - 9y = -9

 \:\:

 \underline{\bold{\texttt{Dividing the above equation by 9}}}

 \:\:

 \bf \dashrightarrow x - y = -1 -------(2)

 \:\:

 \red{\bold{Equation \: (1) \: + \: Equation \: (2)}}

 \:\:

 \sf \longmapsto x + y + x - y = 9 - 1

 \:\:

 \sf \longmapsto 2x = 8

 \:\:

 \sf \longmapsto x = \dfrac { 8 } { 2 }

 \:\:

 \bf \dashrightarrow x = 4 ------(3)

 \:\:

 \underline{\bold{\texttt{Putting x = 4 in (1)}}}

 \:\:

 \sf \longmapsto 4 + y = 9

 \:\:

 \sf \longmapsto y = 9 - 4

 \:\:

 \bf \dashrightarrow y = 5

 \:\:

 \underline{\bold{\texttt{Original number :}}}

 \:\:

\purple\longrightarrow \sf 10(4) + 5

 \:\:

i.e 45 is the original number

\rule{200}5

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