Question

the sum of digit of a two digit number is seven if the number formed by reversing it's digit is less than the original number by 9 find the original number

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Answer 1

Solution:

Let the number be 'xy'.

That is: 10x + y

Now:

Reversing the digits, we get 'yx'.

$\boxed{\sf{yx = 10y + x}}$

And the difference is: 9x - 9y

We get:

$\implies$ 9 (x - y) = 9

$\implies$ 9x - 9y = 9

$\implies$ x - y = 1

Sum of the digits is: x + y = 7

That is:

$\implies$ x = 4

$\implies$ y = 3

So: 4 + 3 = 7

Therefore:

The original number is 43.

Answer 2

Answer:

the original number is 43

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