Question

The sum of digit of a two number is 12.If the new number formed by reversing the digit is greater than the original number by 54? Find the original number

Answer 1

Let the digit at ones place be x and tens place be y
Number = 10y+x
Number we get on reversing the digits 10x+y
According to 1st condition
X+y=12--------------1
According to 2nd condition
10x+y=10y+x+54
9x-9y=54
X-y=6--------------------2
Add equation 1 and 2 we get
2x=18
X=9
Put x=9 in equation 1 we get
Y=3
Hence the number is 39