Question

The sum of digit of two-digit number is 16. If the new number formed by reversing the digits is greater than the original number by 18 , find the original number

Answer 1

Answer:

X+Y=16 ......1st EQ

y+x=18....2nd EQ

solve the equation

Answer 2

Answer:

num is 79

Step-by-step explanation:

let the num be 10x+y

acc to the question..sum of digits is 16--x+y=16----eq(1)

by reversing digits...

10y+x=10x+y+18

from this we get x-y=-2---eq(2)

by adding 1 and 2 we get

x=7...... substitute x=7 in eq(2)

then,y=9

the number is 10x+y=10×7+9

=79