Math, asked by sekharpadhi, 8 months ago

the sum of digit of two digit number is 7 if the digits are reversed the new number decreased by 2 equal to ise the original number find the original number​

Answers

Answered by Anonymous
3

Answer:

25

Step-by-step explanation:

Let the original number be

yx

; i.e., 10y+x. We know x+y=7. The number obtained by reversing the digits in

xy

, i.e., 10x+y. The second condition gives 10x+y−2=2(10y+x). Thus we have two equations:

x+y=7....(1)

8x−19y=2....(2)

Multiply the equation (1) by 19 and get

19x+19y=133.

Adding this to (2), we obtain 27x=135. This gives x=5. Hence y=7−x=7−5=2.

The required number is 25.

Answered by Mahi2605
0

Answer:

Let the original number be

yx

; i.e., 10y+x. We know x+y=7. The number obtained by reversing the digits in

xy

, i.e., 10x+y. The second condition gives 10x+y−2=2(10y+x). Thus we have two equations:

x+y=7....(1)

8x−19y=2....(2)

Multiply the equation (1) by 19 and get

19x+19y=133.

Adding this to (2), we obtain 27x=135. This gives x=5. Hence y=7−x=7−5=2.

The required number is 25

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