the sum of digit of two digit number is 8. the number obtained by interchanging the digit exceed the given number by 18 find the given number
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x + y = 8 {equation 1}
The value of xy is 10x + y
The value of yx is 10y + x
10y + x = 10x + y + 18
9y - 9x = 18
9(y - x) = 18
y - x = 2
From equation 1: y = 8-x
8 - x - x = 2
8 - 2x = 2
-2x = -6
x = 3
y - x = 2
y - 3 = 2
y = 5
Original number xy = 35
plz marked as brainlist answer
x + y = 8 {equation 1}
The value of xy is 10x + y
The value of yx is 10y + x
10y + x = 10x + y + 18
9y - 9x = 18
9(y - x) = 18
y - x = 2
From equation 1: y = 8-x
8 - x - x = 2
8 - 2x = 2
-2x = -6
x = 3
y - x = 2
y - 3 = 2
y = 5
Original number xy = 35
plz marked as brainlist answer
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