The sum of digit of two-digit number is 9 . if the digits are reversed the new number will be 99 more than the original number find the original number.
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Let the digits be x and y and the number be
10x +y
It is given x+y=9
10y+x=99+10x+y
9y-9x= 99
y -x =11
y -x +(x+y)=11+9=20
2y=20
y=10
There's something wrong in the question
y has to come one digit
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