Question

the sum of digit of two number is 9 if the digit interchange their places the new number exceeds the original by 63 the original no is​

Answer 1

Answer:

Step-by-step explanation:

step 1: As the number is two digit, you can write it as (10X + Y)

step 2: sum of the digits is 9. here we get an equation X + Y = 9, lets call it equation 1.

step 3: the the number after interchanging the digits is (10Y + X)

step 4: interchanging the digits reduces the number by 63. so we got one more equation (10Y + X)=(10X + Y) - 63, call it equation 2.

(10Y + X)=(10X + Y) - 63 ..........(2)

rearranging equation...2

10X + Y - 10Y - X = 63

9X - 9Y = 63

dividing equation by 9, we get

X - Y = 7 ..................(3)

step 5: solving simultanious equations (1) & (3)

X + Y = 9

X - Y = 7