Math, asked by QUEEN22x, 5 months ago

The sum of digits in a 2-digit number is 13 and the difference between the number an
that formed by reversing the digits is 27. Find the number.
Guys plz answer it fast tomorrow is my exam i need to prepare it.​

Answers

Answered by aayushsharma7956
2

Answer:

THE NUMBER IS 85

Step-by-step explanation:

LET THE NUMBER BE xy

SO,

GIVEN,

x+y=13

x = (13-y)

SO,

A.T.Q.,

xy-yx = 27

10(x) + y - [10(y)+x]  =27

10(13-y) - y + [10y+(13-y)] = 27

130-10y+y - [ 10y-y+13} = 27

130-9y-9y-13 = 27

130-13-9y-9y = 27

117-18y = 27

-18y = 27-117

-18y = -90

y = -90/-18

y = 5

SO,

x = 13-y

  = 13-5

  = 8

SO,

xy = 85

I HOPE YOU UNDERSTOOD THE QUESTION!!!

                                   !!!JAI SHREE KRISHNA!!!

Answered by assingh
7

Topic

Linear Equations

Given

The sum of digits in a 2-digit number is 13 and the difference between the number and number formed by reversing the digits is 27.

To Find

The number which satisfies given statements.

Solving

Let number be in form of xy.

So, number is 10x + y.

Number formed by reversing the digits is yx.

So, number is 10y + x.

It is given that,

x + y = 13 and

10x + y - ( 10y + x ) = 27

10x + y - 10y - x = 27

9x - 9y = 27

x - y = 27/9 = 3

Now,

x + y = 13

x - y = 3

Add both the equations

2x = 16

x = 8

Put value of x in any equation,

x + y = 13

8 + y = 13

y = 5

Answer

As the number is in xy form, it is 85.

Verification

Number obtained is 85.

8 + 5 = 13

Reversing the number, we get 58.

85 - 58 = 27

The number 85 satisfies the required conditions.

Hence, verified.

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