The sum of digits in a 2-digit number is 13 and the difference between the number an
that formed by reversing the digits is 27. Find the number.
Guys plz answer it fast tomorrow is my exam i need to prepare it.
Answers
Answer:
THE NUMBER IS 85
Step-by-step explanation:
LET THE NUMBER BE xy
SO,
GIVEN,
x+y=13
x = (13-y)
SO,
A.T.Q.,
xy-yx = 27
10(x) + y - [10(y)+x] =27
10(13-y) - y + [10y+(13-y)] = 27
130-10y+y - [ 10y-y+13} = 27
130-9y-9y-13 = 27
130-13-9y-9y = 27
117-18y = 27
-18y = 27-117
-18y = -90
y = -90/-18
y = 5
SO,
x = 13-y
= 13-5
= 8
SO,
xy = 85
I HOPE YOU UNDERSTOOD THE QUESTION!!!
!!!JAI SHREE KRISHNA!!!
Topic
Linear Equations
Given
The sum of digits in a 2-digit number is 13 and the difference between the number and number formed by reversing the digits is 27.
To Find
The number which satisfies given statements.
Solving
Let number be in form of xy.
So, number is 10x + y.
Number formed by reversing the digits is yx.
So, number is 10y + x.
It is given that,
x + y = 13 and
10x + y - ( 10y + x ) = 27
10x + y - 10y - x = 27
9x - 9y = 27
x - y = 27/9 = 3
Now,
x + y = 13
x - y = 3
Add both the equations
2x = 16
x = 8
Put value of x in any equation,
x + y = 13
8 + y = 13
y = 5
Answer
As the number is in xy form, it is 85.
Verification
Number obtained is 85.
8 + 5 = 13
Reversing the number, we get 58.
85 - 58 = 27
The number 85 satisfies the required conditions.
Hence, verified.