Question

the sum of digits in unit place of all the numbers formed with the help of 3,4,5and 6 taken all at a time

Answer 1

Answer:

Step-by-step explanation:

Let 3 be the unit place number, then there are 3 choices for 10th place number, as the 10th place digit can be chose from 4, 5, 6. Similarly there are 2 choices form 100th place digit and 1 choice for 1000th place digit.

Hence there are 3⋅2⋅1=6 numbers ending with 3. These 6 number will add 6×3=18 to the sum of the digits in the unit's place.

Similarly, there will be 6 numbers each ending with 4, 5 and 6 and they will add 4⋅6=24; 5⋅6=30 and 6⋅6=36  to the sum.

Hence, the sum of the digits in the unit's place of all numbers formed with the help of 3,4,5,6 taken all at a times is 18+24+30+36=108.

Answered By

Answer 2

Answer:

Yeah I agrerd. You are very beautiful and handsome.