Question

the sum of digits no is 7 the number obtained by interchanging the digit exceeds the original no by 27 find the number.​

Answer 1

let digit at ones place = x

digit at tens place = y

So, the number will be 10y + x

$x+y=7$

reverse digit will be represented as,

$10x+y$

So,

$(10x+y)-(10y-x)=27 \\ </p><p></p><p>9x-9y=27 \\ </p><p></p><p>x-y=3$

Adding equation (1) and (2)

$2x=10 \\ </p><p></p><p>x=5$

substituting in equation (1)

$y=7-5 \\ </p><p></p><p>=2$

Thus, the number will be 25

Answer 2

Step-by-step explanation:

Let Digit at ones place = x

And, digit at tens place = y

So, the number will be 10y+x

x+y = 7 .... (1)

reverse digit will be represented as, 10x+y

So,

(10x+y)-(10y-x) = 27

9x-9y =27

x-y = 3 ....(2)

Adding equation (1) and (2)

2x = 10

x = 5

substituting in equation (1)

y = 7-5

y = 2

Thus, the number will be 25

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