Question

The sum of digits of a 2-digit no. is 8 and difference of no and obtaining the reversing no. is 18. Find the no.

Answer 1

Let the units place digit be y and tens place digit be x

so the number is

10x+y

By the conditions given in your question we get two equations

x+y=8. ... (1)

10x+y-(10y+x)=18

10x+y-10y-x=18

9x-9y=18

x-y=2. .. (2)

by adding equations (1)&(2)

2x=10

x=5

y=3

so number is 53