Question

The sum of digits of a 2- digit no. is11.If the number obtained by reversing the digits is 9 less than
the original number. Find the number.​

Answer 1

Answer:

original number is 65.

Step-by-step explanation:

Let 2 digits be 'x' and 'y'.

so, x+y = 11 .... (1)

original number= 10x+y

no. obtained by reversing the digit of original number= 10y+x

10x + y = (10y + x) + 9

9x = 9y + 9

x = y + 1

x-y = 1....(2)

Adding eq.(1) and eq.(2)

x+y+x-y=1+11

2x=12

x=6

y= x-1....(from eq.2)

y=6-1

y=5

original number=10(x)+y

=10(6)+5

=65