The sum of digits of a 2-digit number is 11. If the number obtained by reversing the digits is 9 less than the original number, find the number.
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Answered by
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Step-by-step explanation:
Let m and n be the digits of the number. Then:
m+n=11 and
10m+n-9=10n+m
So:
n=11-m
10m+11-m-9=10(11-m)+m
9m+2=110–9m
18m=108
m=6
n=5
The number is 65…………….
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