Math, asked by simi16, 1 year ago

The sum of digits of a 2-digit number is 11. If the number obtained by reversing the digits is 9 less than the original number, find the number.

Answers

Answered by mysticd
228
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Answered by Anonymous
85

Step-by-step explanation:

Let m and n be the digits of the number. Then:

m+n=11 and

10m+n-9=10n+m

So:  

n=11-m

10m+11-m-9=10(11-m)+m

9m+2=110–9m

18m=108

m=6

n=5

The number is 65…………….

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