Question

the sum of digits of a 2-digit number is 9. On reversing it's digits, the number is 18 less than the original number.Find the number​

Answer 1

Answer :

☞solution :

• sum of two digit ( x+y=6 )
• so the first digit is x and second is y

☞ let's think as we h@ve 81 how to describe

• 8 is x and 1 is y so number is 10x+y = 10×8+1 = 81
• now this formula apply

☞equation :

• original number is = 10x+y
• reverse number is = 10y+x
• orignal number is +18 than reverse

• 10x+y = 10y+x+18
• 9x-9y = 18
• x-y = 2

x+y = 6 and x-y = 2

x+y + x-y = 6+2

2x = 8

x = 4 Y = 6-4 = 2

☞ orignal number is 10(4)+2 = 42

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