The sum of digits of a 2digits no.is 13the number obtained by interchange the digits of given number exceed the number 27find the number
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Let the digits of the number be a and b
therefore,a+b=13
the number is 10a+b
when interchanged
we get,10b+a
therefore,(10b+a)-(10a+b)=27
10b+a-10a-b=27
we know a+b=13
then,a=13-b
substituting value of a,
10b+13-b-10(13-b)-b=27
10b-b-130+10b-b=27-13
18b=130+14
b=144/18
b=8
substituting the value of b,
a+b=13
a=13-8=5
therfore,the number is
10a+b=10*5+8
50+8=58
therefore the number is 58
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