The sum of digits of a 3 digit number is 12 the middle digit is eqaual t half the sum of other two. If the order of digits is reversed the number is diminished by 198 find the no.
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➡️heya
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➡️ Let the three digit number be xyz
➡️ ACCORDING TO THE QUESTION
➡️ x + y + z = 12 ..... Equation ( i )
➡️ y = { x + z }/2 .... Equation ( ii )
➡️ 100y + x = 100x + y - 198
➡️ x - y = 2 .... Equation ( iii )
➡️ Solve Equation i and ii we get
➡️ y = 4
➡️ z= 2
➡️ x= 6
So, the three digit number is xyz
I,e 642
_______________________________
➡️ Let the three digit number be xyz
➡️ ACCORDING TO THE QUESTION
➡️ x + y + z = 12 ..... Equation ( i )
➡️ y = { x + z }/2 .... Equation ( ii )
➡️ 100y + x = 100x + y - 198
➡️ x - y = 2 .... Equation ( iii )
➡️ Solve Equation i and ii we get
➡️ y = 4
➡️ z= 2
➡️ x= 6
So, the three digit number is xyz
I,e 642
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