The sum of digits of a four digit natural number is 26. The digits at unit and thousand place are same. The tenth place digit is double of digit at hundredth place and it is greater by 1 than unit place digit, find that number.
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Step-by-step explanation:
suppose thousand place digit= x
unit place digit= x
hundred place digit = y
tens place digit= 2y
By given 1st condition,
x + y + 2y + x = 26
2x + 3y = 26 -------- (1)
By given 2nd condition,
2y - x = 1
i.e - x + 2y = 1 -------- (2)
multiply eqn 2nd by 2
-2x + 4y = 2 -----------(3)
adding eqn 1st and 3rd we get
7y = 28
y = 4
put y= 4 in eqn 1st we get,
x =7
required 4 digit number is 7487
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