The sum of digits of a no. Is 14. If 29 is subtracted from the no. the resultant digits are equal...find the no.........(hope no medium brained or good brained ones can ever do it !!!!)
thesohan:
it came in rmo , i.e Regional maths Olympaid
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Let the Unit digit of the number = x
Tens digit of the number = y
So that the number is x+10y
A/q,
x + y = 14 -------------------(i)
now,
x + 10y - 29 = X + 10Y
x + 1 + 10y - 30 = X + 10Y
(x + 1) + 10(y - 3) = X + 10Y
X = x + 1
Y = y - 3
and,
X = Y
x +1 =y - 3
x - y = -4 ------------------(ii)
Add eqn(i) + (ii)
2x = 10
x = 5
y = 14 - 5= 9
Therefore number is x + 10y = 5 + 10*9 = 95
Tens digit of the number = y
So that the number is x+10y
A/q,
x + y = 14 -------------------(i)
now,
x + 10y - 29 = X + 10Y
x + 1 + 10y - 30 = X + 10Y
(x + 1) + 10(y - 3) = X + 10Y
X = x + 1
Y = y - 3
and,
X = Y
x +1 =y - 3
x - y = -4 ------------------(ii)
Add eqn(i) + (ii)
2x = 10
x = 5
y = 14 - 5= 9
Therefore number is x + 10y = 5 + 10*9 = 95
Answered by
0
Answer:
95
Step-by-step explanation:
sum of digits = 14
let 'x' and 'y' be numbers
29 is subtracted from the number the two digits of the number become equal
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