The sum of digits of a number is 10. If 36 is subtracted from the number the digit interchange their places find each number
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Answered by
3
Answer:
73.
37
Step-by-step explanation:
let the digits be x and y
Number =
=> 10x+y
ATQ,
x+y=10 ---------------(1), &
10x+y-36 =10y+x
=>9x-9y=36
=> x-y =4 -----------------(2)
Add (1) & (2),
x+y+x-y=10+4
2x=14
x=7
y=10-7=3
Initial no. -: 10(7)+3 = 73
Final no. -: 10(3)+7 = 37
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