The sum of digits of a number is 12. If both are interchanged, then the newly formed number is 36, more than the original number. What is the original number?
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Sum of the digit is 12
x+y = 12 …….(1)
The no is 10x+ y
Reversing the digit ,the new no is 10y +x
According to the condition
10y+ x = 10x +y+ 36
-9x+9y = 36
Dividing by ‘9’
-x+y= 4 ……(2)
Adding the equations (1)& (2)
2y = 16
y= 8
Substituting value of y in first equation , value of x is 4
x= 4
The no is 48
for verification sum of the digits x+ y = 4+ 8 = 12
Interchanging the digit is 84 this no is 36 more than the original no , 48 + 36 = 84
The original number is 48
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