Question

the sum of digits of a two digit no. is 13 .if sum of their squares is 89,find the no.​

Answer 1

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Answer 2

Answer:

Let,the two digits are x & y.

given ,

x+y= 13

i.e. x=13-y-----(1)

&

x^2+y^2=89

i.e. (13-y)^2+y^2=89 [from (1)]

i.e. 169-26y+y^2+y^2=89

i.e. 2y^2-26y+80=0

i.e. y^2-13y+40=0

i.e. y^2-8y-5y+40=0

i.e. y(y-8)-5(y-8)=0

i.e. (y-5)(y-8)=0

i.e. y= 5,8

now, putting y=5 in (1)

x=13-5

=8

putting y=8 in (1)

x=13-8

=5

therefore,the no are x=8,5

& y=5,8

Step-by-step explanation:

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