Question

The sum of digits of a two digit no is 8. If difference between the

Reverse no and original no is 18. Find the number​

Answer 1

Answer:

Step-by-step explanation:

Let the unit's digit be x and tens digit be y

So according to the question,

x+y=8. eq 1...

The two digit number is in the form 10y+x

Reverse number =10x+y

according to the question,

10x+y-(10y+x)=18

10y+x-10x-y=18

-9x+9y=18

(÷9)

-x+y=2

y=2+x eq 2...

Equating eq1 and eq2 we get,

2+x+x=8

2x=6

x=3

Therefore y=2+x

y=5

HOPE THIS HELPS YOU

Answer 2

Answer:

Step-by-step explanation:

Solution:-

Let the unit place digit be x.

And the tens place digit be y.

Number = 10y + x

Reversed Number = 10x + y

According to the Question,

⇒ x + y = 8 ... (i)

⇒ (10y + x) - (10x + y) = 18

⇒ 10y + x - 10x - y = 18

⇒ 9y - 9x = 18

⇒9(y - x) = 18

⇒ y - x = 18/9

⇒ y - x = 2 ... (ii)

Solving Eq (i) and (ii), we get

⇒ y = 5

Putting y's value in Eq (i), we get

⇒ x + y = 8

⇒ x + 5 = 8

⇒ x = 8 - 5

⇒ x = 3

Hence the required number is 53.