Question

The sum of digits of a two-digit number is 10 if you reverse the digits the new number will be 54 more than the original number what is the original number The sum of digits of a two-digit number is 10 if we reversed the digits the number would be 54 more than the original

Answer 1

tens digit= y
ones digit =x
y+x=10                                    (1)
(10y+x)+54=(10x+y)
9y-9x=-54                                (2)
multiply (1) by 9
ie. 9y+9x=90                              (3)
add (2), (3)
9y-9x=-54
9y+9x=90
--------------
18y=36
=> y=2                                        (i)
put value of y in (1)

2+x=10
=> x=8

now, no. is 10y+x
ie.
28