Question

The sum of digits of a two digit number is 11.If the digit at ten's place is increased by 5 and the digit at unit's place is decreased by 5,the digits of the number are found to be reversed.Find the original number.

Answer 1

Let us assume, x is a tenth place digit and y is the unit place digit of a two-digit number.

Therefore, the number = 10x + y and the reversed number = 10y + x

Given:
x + y = 11 -----------1

Also given:

10(x + 5) + y - 5 = 10y + x
10x + 50 + y - 5 = 10y + x
10x + y + 45 = 10y + x
9y - 9x = 45
y - x = 5 ---------------2

Adding equation 1 and equation 2
2y = 16
y = 8

Therefore, x = 11 - y = 11 - 8 = 3
Therefore, the two-digit number = 10x + y = 10*3 + 8 = 38

Answer 2

I hope that it helps u!...