Question

the sum of digits of a two digit number is 11. If the figit at ten's palce is increased by 5 and at the unit place is decreased by 5 tje digits of the number are found to be reversed,.Find the orignal number​

Answer 1

let the digits at ones and tens place be a, b respectively.

given that :-

b + a = 11

10(b+5) + (a-5) = 10a + b

=> 10b + 50 + a - 5 = 10a + b

=> 9a - 9b = 45

=> a - b = 5

solving our final equation with our orginal one, we get -

a = 8, b = 3

so our orginal number is 38