Question

The sum of digits of a two digit number is 11. If we interchange the digits then the new number formed is is 45 less than the original number. Find the original number. I will mark him/her brainliest who give correct answer with explanation.​

Answer 1

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Let us assume that, the original number is

(10x + y) where y is unit digit, and x is ten's

digit.

SO,

→ x + y = 11 (given) Eqn.(1)

now, after interchanging,

→ Number becomes (10y + x)

A/q,

(10x+y)(10y + x) = 45

→ 10x - x + y - 10y = 45

→ 9x - 9y = 45

→ x - y = 5 Eqn.(2)

adding Eqn.(1) and Eqn.(2)

→ x + y + x - y = 11+5

→ 2x = 16

-x=8

O LTET 47 all all

then,

→ 8 + y = 11

→y = 11 - 8 = 3.

therefore,

therefore,Original number = 10x + y = 10*8 + 3 = 83

Answer 2

Given :- The sum of digits of a two digit number is 11. If we interchange the digits then the new number formed is is 45 less than the original number. Find the original number.

Answer :-

Let us assume that, the original number is (10x + y) where y is unit digit , and x is ten's digit .

so,

→ x + y = 11 (given) -------- Eqn.(1)

now, after interchanging,

→ Number becomes = (10y + x)

A/q,

→ (10x + y) - (10y + x) = 45

→ 10x - x + y - 10y = 45

→ 9x - 9y = 45

→ x - y = 5 ---------- Eqn.(2)

adding Eqn.(1) and Eqn.(2)

→ x + y + x - y = 11 + 5

→ 2x = 16

→ x = 8

then,

→ 8 + y = 11

→ y = 11 - 8 = 3 .

therefore,

→ Original number = 10x + y = 10*8 + 3 = 83 (Ans.)

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