Question

the sum of digits of a two digit number is 12.If the new number formed by reversing the digits is greater than the original number by 18. Find the original number.​

Answer 1

Step-by-step explanation:

It is also given that the new number formed by reversing the digits is greater than the original number by 54. We have assumed the number is 10x +y. On putting the value of x and y we get 10(3) + 9 =39. Hence the number is 39.

Answer 2

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the sum of digits of a two digit number is 12.If the new number formed by reversing the digits is greater than the original number by 18. Find the original number.

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Let x be the unit digit and y be tens digit.

⇝Then the original number be 10x+y.

Value of the number with reversed digits is 10y+x.

As per question, we have

⇝x+y=12 ....(1)

If the digits are reversed, the digits is greater than the original number by 18.

Therefore, 10y+x=10x+y+18

⇝9x−9y=−18 ....(2)

Multiply equation (1) by 9, we get

⇝9x+9y=108 ....(3)

Add equations (2)and (3),

18x=90

⇒x=5

Substitute this value in equation (1), we get

5+y=12⇒y=7

Therefore, the original number is 10x+y=10×5+7=57..

⇝10x+y=57