Question

The sum of digits of a two digit number is 12. If the number is increased by 18, its digit gets reversed. The number is

??!:

Answer 1

Explanation:

EXPLANATION.

Let the digit at tens place be = x

Let the digit at unit place be = y

Original number = 10x + y

reversing number = 10y + x

The sum of digit of a two digit number = 12.

=> x + y = 12 .......(1)

If the number is increased by 18 it's digit reversed.

=> 10y + x = 10x + y + 18

=> 9y - 9x = 18

=> y - x = 2 .......(2)

From equation (1) and (2) we get,

=> 2y = 14

=> y = 7

Put the value of y = 7 in equation (1) we get,

=> x + 7 = 12

=> x = 5

Therefore,

original number = 10x + y = 10(5) + 7 = 57.

Answer 2

Answer:

$\mapsto$Let the unit digit be x,

=> and , tens digit be y.

→A/Q

↪➡ x + y = 12. .....................(1).

=> The real number is x + 10y.

=> And the reversed number is 10x + y.

▶⏩Now,

↪➡ x + 10y + 18 = 10x + y.

↪➡ 10y - y + 18 = 10x -x.

↪➡ 9y + 18 = 9x.

↪➡ 18 = 9x - 9y.

↪➡ 9x - 9y = 18.

↪➡ 9( x - y ) = 18.

↪➡ x - y = 18/9.

↪➡ x - y = 2. ......................(2)

▶⏩ Add in equation (1) and (2).

↪➡ x + y + x - y = 12 + 2.

↪➡ 2x = 14.

↪➡ x = 14/2.

→ x = 7.

=> put the value of ‘x’ in equation (2).

↪➡ 7 - y = 2.

↪➡ -y = 2 - 7.

→ y = 5.

▶⏩ Hence, the obtained number is:-)

↪➡ x + 10y.

= 7 + 10 × 5.

= 57.

Explanation:

Please Make As Brainlist Answer