Math, asked by AkShAyKrIzZ192, 1 year ago

The sum of digits of a two digit number is 12.The number obtained by interchanging the numbers exceeds the given number by 18.Find the number............???????????? Fast help I will mark the answer as BRAINLIEST if it is the answer

Answers

Answered by gaurav2013c
4
Let the tens place digit be a

And ones place digit be b

First condition,

Sum of digits = 12

=> a+b = 12

=> a = 12-b ------(1)

Second condition,

10a +b = 10b+a - 18

=> 10a+b-10b-a = - 18

=> 9a-9b = - 18

=> a - b = - 2

=> 12-b - b = - 2 (using equation 1)

=> 12 - 2b = - 2

=> 12+2 = 2b

=> 2b = 14

=> b = 7

a= 5


Required number = 57



Answered by Vidushisharmahwr
2
See the attachment of the phito it has the complete solution and if tgere are any questions please do ask.
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