the sum of digits of a two digit number is 12 the number is obtained by their interchanging of its digit exceeds the given number by 18 the number is
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x+y=12
x=unit place
y=ten place
10y+x+18=10x+y
9y-9x=18
y-x=2
y+x=12
x=5,2y=14
y=7
x=unit place
y=ten place
10y+x+18=10x+y
9y-9x=18
y-x=2
y+x=12
x=5,2y=14
y=7
thanks for the answer
i am a girl
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