The sum of digits of a two digit number is 13. If sum of their squares is 89, find the
number.
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Let the tens place digit be x and the units place digits be y
so by the condition given in the question
x+y=13. ----1
x^2+y^2=89
by squaring both the sides of equation 1 we get
x^2+2xy+y^2=169
89+2xy=169
2xy=169-89
xy=40
so
(x-y)^2=x^2-2xy +y^2
=89-80
=9
(x-y)^2=9
by taking square root of both the sides we get
x-y=3. ---3
by adding equation 1 and 3 we get
2x=16
x=8
y=5
so the number is 85
so by the condition given in the question
x+y=13. ----1
x^2+y^2=89
by squaring both the sides of equation 1 we get
x^2+2xy+y^2=169
89+2xy=169
2xy=169-89
xy=40
so
(x-y)^2=x^2-2xy +y^2
=89-80
=9
(x-y)^2=9
by taking square root of both the sides we get
x-y=3. ---3
by adding equation 1 and 3 we get
2x=16
x=8
y=5
so the number is 85
Sarth45:
please tell wether my answer is right or wrong
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