The sum of digits of a two digit number is 13. If the number formed by
reversing the digits is less than the original number by 27, find the original
number.
Answers
Answered by
3
Let the no. be (10x + y).
Let the reversed no. be 10y + x.
(10x + y) - (10y+x) = 27
10x + y -10y -x =27
9x - 9y= 27 ......equation 1
x + y =13
x= 13 - y .
Put the vale of x in equation 1 and get y.
Substitute the value of y and get x.
Let the reversed no. be 10y + x.
(10x + y) - (10y+x) = 27
10x + y -10y -x =27
9x - 9y= 27 ......equation 1
x + y =13
x= 13 - y .
Put the vale of x in equation 1 and get y.
Substitute the value of y and get x.
ahmedabdulaziz:
this is wrong
Answered by
3
The original number is 85
As 8+5= 13
And reverse of 85= 58
So 85-58=27
As 8+5= 13
And reverse of 85= 58
So 85-58=27
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