Question

The sum of digits of a two digit number is 15. If the number formed by reversing the

digits is less than the original number by 27. Find the original number.​

Answer 1

Step-by-step explanation:

let the digits be x and y

then

x+y=15 i

10x+y=10y+x-27

9x-9y= -27

x-y= -3 ii

from i and ii we get

x= -6 and y=21

no=39

Answer 2

Step-by-step explanation:

Let the numbers unit place is y.and the tenth place is x.

Then, the number is 10x+y.

Then,

x+y =15—i

Then,

10x+y–(10y+x)=27

or, 10x+y–10y–x=27

or,9x–9y=27

or,9(x–y)=27

or, x–y=3—ii

on, solving iand ii equation ,we get x=9

and y=6 Then the original number is 96.