Question

the sum of digits of a two digit number is 7 and the ten's place digit is 25% less than the unit's place digit.what is the number?​

Answer 1

Answer:34

Step-by-step explanation:

Let the ones place be x then tens place =3x/4

x+3x/4=7

7x/4=7

x=4

The no is 34

Answer 2

Answer:

37

Step-by-step explanation:

Let the digit of unit place be x

We are given that the ten's place digit is 25% less than the unit's place digit

Ten's place digit = $x-\frac{25}{100}x = 0.75x$

Let the digit of tens place be y

We are given that the sum of digits of a two digit number is 7

So, $x+0.75x=7$

$1.75x=7$

$x=\frac{7}{1.75}$

$x=4$

So, unit's place digit is 7

Ten's place digit = 0.75*4 = 3

Hence the number is 37