Question

The sum of digits of a two digit number is 7 . If 5 times of ten digit is 2 less than half of the number. Find the number.​

Answer 1

Answer:

Let the ones's digit =x.

So, sum of the digits =7

Tens's digit =7−x

Original no. =10(7−x)+x=70−10x+x=70−9x

Reversed no. =10x+7−x=9x+7

2(orig no) = reversed no. −2

2(70−9x)=9x+7−2

140−18x=9x+5

27x=135

x=5

Ten's digit =7−5=2

No. =25

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Answer 2

Step-by-step explanation:

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