Question

The sum of digits of a two-digit number is 7. The number obtained by interchanging the digits
exceeds the original number by 45. Find the number.

Answer 1

Answer:

BlueJ

Step-by-step explanation:

LOL!

Answer 2

Answer:

16.

Step-by-step explanation:

Let the ones digit be x and tens digit be y.

so number will be 10y+x

according to question

x+y=7 I)

x=7-y

And now number obtained by interchanging digits exceeds original number by 45.

so,

10x+y=(10y+x)+45

9x-9y=45

x-y=5 ii)

on solving eq. I and ii we get

x=6

y=1

putting this in 10y+x we get the number =16.

Hope it helps.