The
sum of digits of a two digit number is
8 and the different between the number
and that formed by reversing the digits
18. Find the number.
Answers
Answered by
3
Answer:
16,4 is the ans of question
Answered by
7
Answer:
Let the unit place digit be x
and tens place digit be y
number formed by x and y =10 y + x
number obtained by reversing digits = 10 x + y
here, sum of digits =8(1)
and difference on reversing the digit is 18
A/q
(10y-x)-(10x+y)=18
or,(10y+x)-(10x-y)=18
or,9y-9x=18
or,9(y-x)=18
or,y-x=18/9=2
on adding both the given equation
Now, y + x = 8
y - x = 2
_________
2y. =10
or,. y =5
now putting the value of y in equation 1st
y+x=8
5+x=8
or,x=3
now the formed number= 53
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