Question

the sum of digits of a two digit number is 9 also nine times this number is twice the number obtained by reversing the order of digits

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Answer 1

Answer:

18

Step-by-step explanation:

Let the number be 10a + b.

Given - a+b = 9 ---(1)

also, 9(10a+b) = 2(10b +a)

90a +9b = 20b + 2a

88a = 11b

8a - b = 0 -----(2)

by adding the equations (1) and (2),

9a = 9

a = 1

by putting this value in (1),

b= 8

Therefore, the number is 10a +b = 18