Question

The sum of digits of a two digit number is 9.Also,nine times this number is twice the number by reversing the order of the number .Then the number is.........?....?​

Answer 1

Answer:

18

Step-by-step explanation:

your answer is in the attachment

Answer 2

${\huge {\mathfrak {Answer :-}}}$

✨Let the ones digit of the number be 'x' and tens digit be 'y'.

◾Given,

${} \implies x + y = 9$

${} \implies y = 9 - x$

◾Now,

The number is

= $<b>10x + y </b>$

Reversing the digits

= $<b> 10y + x </b>$

◾By condition,

${} \implies 9(10x + y) = 2(10y + x)$

${} \implies 90x + 9y = 20y + 2x$

${} \implies 88x - 11y = 0$

${} \implies 8x - y = 0$

${} \implies 8x - 9 + x = 0$

${} \implies x = 1$

And, y = 9 - 1 = 8.

◾So,

The number is

= 10(1) + 8

= 10 + 8

= 18

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