Question

The sum of digits of a two digit number is 9.if 27 is shbtracted from the numberthe digits are reversed

Answer 1

may this will help u...

Answer 2

$\mathfrak{Step-by-Step\:Explanation:}$

Let the tens place digit be x and ones place digit be y.

So

x + y = 9 .....(i)

$\boxed{\bold{A\;two\:digit\:No.=10\times tens\:place\;digit+ones\:place\:digit}}\\\\\\\tt{=10x+y.}$

$\bold{Reversed\:No.=10y+x.}\\\\\\\bold{According\:to\:question,}\\\\\\\implies\bold{10x+y-27=10y+x}\\\\\\\implies\bold{10x-x+y-10y=27}\\\\\\\implies\bold{9x-9y=27}\\\\\\\implies\bold{9(x-y)=27}\\\\\\\therefore\bold{\quad x-y=3.......(ii)}\\\\\\\underline{\bold{Adding\:both\:eq.\;either\:side,}}\\\\\\\implies\bold{x+y+x-y=9+3}\\\\\\\implies\bold{2x=12}\\\\\\\implies\bold{x=\dfrac{12}{2}=6.}\\\\\\\underline{\bold{Put\:the\:value\:of\:x\:in\:eq.\:(i)}}$

$\implies\bold{6+y=9}\\\\\\\implies\bold{y=9-6}\\\\\\\implies\bold{y=3.}\\\\\\\boxed{\boxed{\bold{No.=10x+y=60+3=63.}}}$