The sum of digits of a two digit number is 9. If 27 is subtracted from the number we get a two digit number with the sequence of digits changed. Find the number.
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Answer:63
Step-by-step explanation:
Let the two digits be x and y.
Therefore,as per the question,
x+y=0...I
Now, after subtracting 27 from the number, the digits get reversed.
So, 10x+y-27=10y+x
=>9x-9y-27=0
=>x-y-3=0[dividing both sides by 9 ]...ii
Now, adding I and ii we get,
2x-12=0
=>x=6
Therefore,y=9-6=3
Therefore the required number is 63.
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