Question

The sum of digits of a two digit number is 9. Take digit in 10 th place as x and the digit in unit place as y form an equation using this idea ? b) Write the number ? c) If the digits are interchanged the number so obtained is 27 more than the actual number . Using this idea form an equation ? d) Find the actual number ?

Answer 1

Answer:

this is 10 th class example so it is a textbook example of 10th state board book kindly find in it

Answer 2

Answer:

Original Number = 36 Reversed Number = 63

Step-by-step explanation:

Let the unit digit be y and tens digit be x

Number formed = 10x + y

Reverse number = 10y + x

x + y = 9 (Given)…………………………eq1

10y + x = 10x + y + 27…………………….eq2

9y - 9x = 27

y - x = 3……………………………………..eq3

Solving eq1 and eq3 ,we get

x = 3 and y = 6

Original Number = 36

Reversed Number = 63

You can crosscheck the answer by putting up the values obtained either in eq1 or eq2 or eq 3

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