Question

The sum of digits of a two-digit number is 9. the difference between the number obtained by interchanging the digits of the two-digit number and the original number is 45. what is one-fourth of that two-digit number?

Answer 1

let ones digit be x and tens digit be y
then the no. is 10y+x

now ACC to question
X+y=9
also 10y+X - (10x+ y) = 45
10y+x-10x-y=45
9y-9x= 45
y-x=5


after that u can find the values by eliminating