Question

The sum of digits of a two digit number is 9.
The number obtained by interchanging the
digits exceeds the original number by 45. Find
the number​

Answer 1

Answer:

The number is 27 !

Step-by-step explanation:

Take the middle number between 1 - 100: 50

Divide 45 by 2 : 22.5 rounded to 23

Find the difference between the numbers 50 and 23: 27

Closest number divisible by 9: 27 is divisible by 9

Interchange the digits: 72

Find the difference: 72 - 27 = 45

So the answer is 45. :)

Answer 2

Answer:

The number is 27

Step-by-step explanation:

Let the digit in unit's place be x

Then digit in tens place will be (9-x)

Hence

The original number is (tens place + ones place)

= 10(9-x)+x

Interchanging digits = 10x+(9-x)

According to question

10x+(9-x) = 45+ 10(9-x) +x

10x +9-x = 45+ 90 - 10x +x

9x +9 = 135 - 9x

9x + 9x =135-9

18x = 126

X= 126/18

X = 7

Therefore the digit in units place is 7

And digit in tens place =(9-7)= 2

The number is 10(2)+7=

27