The sum of digits of a two digit number is 9. The number obtained by reversing the order of digit is 27 more than the original number .find the original number.
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Answer:
Step-by-step explanation:
Let tens Digit to be x
Unit Digit to be y
According to question
x+y=9
x=9-y.....(1)
10y+x=10x+y+27
10y-y+x-10x=27
9y-9x=27
x-y=3
x=3+y.....(2)
From EQ 1 n 2 we get,
9-y=3+y
6=2y
y=3
Put the value in equation 2
x=6
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