Math, asked by ManishaSachdeva, 1 year ago

The sum of digits of a two digit number is 9. The number obtained by reversing the order of digits is 27 more than the original number. Find the original number.​


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Answers

Answered by rajiv373
0

Let X be the number at the tens place let by be the number at the ones place there for the decimal expansion is 10 x + Y the difference between the two number is given as 3 their 4 x minus y is equals to 3 given that the ratio between two digit number and the number obtained by reversing the number is 427 therefore 10 X + Y divided by 10y + x is equals to 427 / 7 7 x 10 x + Y is equals to 4 x 10 Y + x 70 X + 7 Y is equals to 40 X + 4 x 66 x is equal to 33 Y 66 X into 3 + Y is equal to 30 31 198 + 66 Y is equal to 33 why 198 is equals to 33 Y - 66 y 198 + 66 Y is equal to 33 by 198 is equal to 33 Y - 66 why 198 is = 2 - 33 by 198 / - 33 is equals two y y is equals to minus 6 minus x is equal to 3 x minus minus 6 is equal to 3 X is equals to minus 3

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