The sum of digits of a two digit number is a if the new number formed by reversing the digits is greato than the original number by 45, Find the original number.
Answers
Answered by
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Step-by-step explanation:
Lex 1st (unit) digit = x
let tens no be =9-x
original no.
= 10 (9 - x) + x + 45 = 10x 9 - x
90 - 10x + x + 45 = 9x +9
135-9x=9X+9
126=18x
X=7
Original number=10(9-7)+7
=20+7
=27
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Answered by
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Answer:
Let ones digit =x
Tens digits = a-x
Original no = 10a-9x
New no. = 9x+a
10a-9x+45=9x+a
9a-18x=45
Step-by-step explanation:
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