Question

the sum of digits of a two digit numbet is 9,if the new number is formed by reversing the digits is greater than the original number by 45.find the original number.

Answer 1

Answer:

Step-by-step explanation:

Step-by-step explanation:  Let a be the unit digit and b be the ten's digit of the given two digit number

a+b=9⟹a=9−b  

10a+b+45=10b+a  

⟹10(9−b)+b+45 = 10b+9−b  

⟹90−10b+b+45 = 9b+9  

⟹(135−9b)+9b = (9b+9)+9b  

⟹(18b+9)−9 = 135−9  

⟹18b/18=126/18  

→b=7 and a=2  

answer:27  

Proof:

2+7=9  

27+45=72